Hello,

I just started playing Roulette. I noticed that Red & Black has consistent "repeaters" that can be taken advantage of.

But I know that the problem with chasing repeaters is - there will also be strings of alternating Red/Black that will result in losing streaks.

I've been playing on Practice / Fun mode for several days and I have observed that the longest string of "alternating Red/Black" is 14-in-row.

Can someone here please tell me what the "technical" longest streak would be if this simple method is tested?

Thanks!

Simeon

I just started playing Roulette. I noticed that Red & Black has consistent "repeaters" that can be taken advantage of.

But I know that the problem with chasing repeaters is - there will also be strings of alternating Red/Black that will result in losing streaks.

I've been playing on Practice / Fun mode for several days and I have observed that the longest string of "alternating Red/Black" is 14-in-row.

Can someone here please tell me what the "technical" longest streak would be if this simple method is tested?

Thanks!

Simeon

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RP501:

Can someone here please tell me what the "technical" longest streak would be if this simple method is tested?

Hello and welcome to youroul.com!

There is no limit.

The probability (with zero ignored!) to have an easy chance repeated:

one time: 1/2 ^^1 = 50% 1 out of 2

two times: 1/2 ^^2 = 25% or 1 out of 4

three times: 1/2 ^^3 = 12.5% or 1 out of 8

...

14 times: 1/2 ^^14 = 0.006103516% (0.000061035) or 1 out of 16384 (0.000061035 ^^-1)

...

never ending but quite less probable

A test with 10.000.000 spins will statistically show a row of 23.253496664 times red.

It doesn't matter if you watch for one color or patterns like red / black.

Of course you can run tests on various roulette strategies with those figures,

you will get this results on the long run.

Regards, trizero

trizero:

Hello and welcome to youroul.com!

Thank you for all the INFO! =)

RP501:trizero:

Hello and welcome to youroul.com!

Thank you for all the INFO! =)

I also thank you very much for this explanation!